#2 Calculate strong force coupling constant at 1 TeV

The coupling constant is given by alpha=12*pi/((33-2*nf)*ln(E^2/lambda^2))

where nf = number of quark flavors = 6 and lambda is taken as 0.2 GeV

The value of the coupling constant at different energies is then

E | E(MeV) | alpha(strong) |

1MeV | 1 | -0.169411879 |

100 | -1.294960041 | |

1GeV | 1000 | 0.557708933 |

100000 | 0.144433549 | |

1TeV | 1000000 | 0.105386585 |

#9 Decays of the top quark

The expected decays will produce a bottom quark and a W+, so you look
as what a W+ will produce

The possibilities include positron and electron neutrino, muon+ and
muon neutrino, tau+ and tau neutrino

It can also decay into quarks like and up and an antidown, a charm
and an antistrange, so mesons can be produced.

One of the channels above produces a prompt muon, but the decay of
the bottom quark is likely to produce

muons from all of the decay schemes.

#13 The gamma plus proton are of extremely high energy, and can
therefore produce heavier particles.

gamma + p -> n + Dzero antiparticle + Dplus, antiDzero->Kplus + piminus,
Dplus->Kminus + piplus + piplus

gamma + P->antiDzero + lambdaplus(charmed); antiDzero->Kplus
+ piminus,lambdacplus->p + Kminus + piplus

#14 Ten decays of the D+ meson.

You expect those products with K's in them to be preferred since it
is the next step down in charged mesons

Some possibilities are shown.

#17 The lifetime is given by the expression tau= hbar/gamma

To calculate, use tau = hbar*c/(lambda*c)=0.197 GeV fm/(lambda*c)

Half width lambda using base as about 5 in figure 18-23 gives lambda
= 2 GeV

Using zero as the base gives half width of about 2.2 GeV

tau

lambda=2 gives lifetime 3.28E-25

lambda=2.2 gives lifetime 2.98E-25